00006
Circuit Analysis
circuit06.png

A direct-current potential of [V] Volts is supplied to the circuit by `V_s`. The positive terminal of the voltage supply is at the top in the figure.
The values of each resistor are `R_1=[A]\Omega`, `R_2=[B]\Omega`, `R_3=[C]\Omega`, and `R_4=[D]\Omega`.
What is the current through `R_3`?
[I] mA
[W] mA
[X] mA
[Y] mA
[Z] mA
[U] mA
[S] mA
5
V
5
2
15
A
30
20
490
B
100
50
400
C
80
40
480
D
120
60
480
K
2 + [B]
E
[A] + ( [B] + [D] ) * [C] / ( [B] + [C] + [D] )
S
[V]/[E]
I
1000 * [S]*([B]+[D])/([B]+[C]+[D])
U
1000 * [S]
W
500 * [S]*([B]+[D])/([B]+[C]+[D])
X
1000 * [S]*([A]+[D])/([A]+[C]+[D])
Y
1000 * [S]*([D])/([B]+[C]+[D])
Z
1000 * [V] / ( [B] + [C] )
4
The current supplied by the power source can be found by calculating the equivalent circuit resistance.
blank.png
black
The equivalent circuit resistance, `R_\text{eq}`, is found by adding resistors in series and finding the reciprocal of the sum of reciprocals for parallel resistors.
blank.png
green
For parallel resistors, it is often easier to use "product over sum", such as `\frac{R_A\cdot R_B}{R_A+R_B}`
blank.png
black
`R_\text{eq}=R1+\frac{R3(R2+R4)}{R3+R2+R4}`
blank.png
green
The current divider formula is one shortcut for finding current through one of several parallel resistors. Remember, more current will flow through the resistor with less resistance. With this knowledge, you can set up the equation appropriately.
blank.png
black
The formula for resistor 3 is `I_3=I_s\frac{R2+R4}{R3+R2+R4}`.
blank.png
green
`R_\text{eq}` = [E] `\Omega`
blank.png
orange
`I_s` = [S] A
blank.png
orange
`I_3` = [I] mA
blank.png
red
circuit06exp.png
The current through `R_3` is calculated by determining an equivalent resistance for the right side of the circuit using `R_\text{right}=R_2+R_4`, which is then used to construct a "current divider" equation:<br>
`I_3=I_s\frac{R_\text{right}}{R_\text{right}+R_3}`<br>
Further explanation...
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/ohmlaw.html
HyperPhysics - Ohm's Law
00000
Title
orange.png

The problem statement <VAR>X</VAR>... `\frac{2x}{Y}` Long problem statement. [Q]. Long problem [Q] - [X] statement. Long problem
statement. Long problem statement. Words and words and words, and words.
What is the question?
Answer `1`
Answer `2`
Answer `3`
Answer `4`
Answer `\frac{10}{2}`
Answer `3+3`
Answer `\text{seven}`
5
X
5
2
15
Q
32
0.5
34
Y
5*[X]
4
This first hint; tip of the iceberg. `F=kx`
orange.png
red
Hint 2 is revealed. Words words words text words blah words words words words blah blah text words words words words words.
orange.png
#0000FF
Here is hint 3.
orange.png
green
Hint 4 text is shown, `\frac{A}{B}`.
orange.png
red
FIVE HINT text is shown, `\sqrt{25}`.
orange.png
black
orange.png
This is an explanation.
http://www.LINK.com
Hyperlink Text